This week we learned how to solve word problems in Calculus. I do not really understand this too well but I'll try my best to explain it. NOTES: Step one to solve Related Rates is identify all given quantities and quantities to be determined. Make a sketch and label the quantities. Step two is write and equation involving the variables whose rates of change either are given or are to be determined. Next, Using the Chain Rule, implicitly differentiate both sides of the equation with respect to time t. And Last, substitute into the resulting equation all known values for the variables and their rates of change. Then solve for the required rate of change.
The problem I have is "the easiest part to solving these types of problems". I do not know how to identify all the given information, this is the first step so I can't even begin to start the word problems.
I can, however, take a derivative of an equation you might find in a problem like this...
1.x=2 dx/dt=5
2.y=x^2
3.1(dy/dt)=2x(dx/dt)
4.(dy/dt)=2(2)(5)
(dy/dt)=20
No comments:
Post a Comment