Monday, November 15, 2010

Week 5 Blog Prompt

Using Calculus how can you find a max or a min? How do you determine if the value is a max or min?

6 comments:

  1. Finding a max or min is the same thing as finding a horizontal tangent line.
    STEPS:
    1. Take derivative, and set equal to 0.
    2. Find any place the function is not
    differentiable.
    3. Plug in to get y-value if asking about max or
    min specifically.
    4. If on an interval plug in to get a y-value.
    5. Highest > max
    Lowest > min

    Example:
    1) f(x) = t/t-2 (3,5)
    1. f'(x)= -2 = 0
    x = 0
    2. aymptote at 2
    3. h'(0)= 0
    4. h(3) = 3
    h(5) = 5/3
    5. max > 3
    min > 0

    ReplyDelete
  2. When finding the max and min using calculus
    there are 6 different steps that you use in doing so:

    1. take the derivative and set it equal to 0.
    solve for x.

    2. find any place the function is not differentiable.

    3. plug in to get a y value if asking about a
    max or min specifically.

    4. if on an interval plug into get a y value

    5. highest- max, lowest- min

    the highest number that you end up with max.
    the lowest will be your min.

    ReplyDelete
  3. Finding the max and min of an equation is all about the steps. If you know you’re steps it is manageable, but with out the steps it is IMPOSSIBLE. So I will say this, MAKE SURE YOU KNOW YOUR STEPS FOOLS.
    Here are the sacred STEPS of which I speak of :
    1. Take the derivative and set it equal to 0.
    2. Find any place the function is not differentiable, such as cusps, corners, etc.
    3. Plug in to get a y-value if asking specifically about a max or min.
    4. Make sure you set of your intervals so you can plug in a number from each interval.
    5. Highest number is your max
    Lowest number is your min

    Example:
    1) f (x) = x / x - 4 (3,5)
    1. f' (x)= -4 = 0
    x = 0
    2. aymptote at x = 4
    3. f' (0)= 0
    4. f (3) = -3 f(5) = 5
    5. max = 5 min = -3

    ReplyDelete
  4. Finding a max or min is pretty easy, even though I definitely failed it on that last test, all it really is, is following the steps from our notes...

    STEPS:
    1. Take derivative, and set equal to 0.

    2. Find any place the function is not
    differentiable.

    3. Plug in to get y-value if asking about max or
    min specifically.

    4. If on an interval plug in to get a y-value.

    5. The highest answer you get is your max.
    The lowest answer is your min.

    ReplyDelete
  5. When finding the max and min using calculus there are 6 different steps. The steps that you have to use to find the max or min are:
    1. take the derivative and set it equal to 0. solve for x.
    2. find any place the function is not differentiable.
    3. plug in to get a y value if asking about a max or min specifically.
    4. if on an interval plug into get a y value
    5. highest- max, lowest- min
    the highest number that you end up with max. the lowest will be your min.

    Example:
    f(x) = t/t-2 (3,5)
    1. f'(x)= -2 = 0
    x = 0
    2. aymptote at 2
    3. h'(0)= 0
    4. h(3) = 3
    h(5) = 5/3
    5. max > 3
    min > 0

    Example:
    1) f (x) = x / x - 4 (3,5)
    1. f' (x)= -4 = 0
    x = 0
    2. aymptote at x = 4
    3. f' (0)= 0
    4. f (3) = -3 f(5) = 5
    5. max = 5 min = -3

    ReplyDelete
  6. When finding the max and min using calculus
    there are 6 different steps that you use in doing so:

    1. take the derivative and set it equal to 0.
    solve for x.

    2. find any place the function is not differentiable.

    3. plug in to get a y value if asking about a
    max or min specifically.

    4. if on an interval plug into get a y value

    5. highest- max, lowest- min

    the highest number that you end up with max.
    the lowest will be your min.

    ReplyDelete